string manipulation in Unix Shell Scripting

[biot023]

Hallo.
I can't seem to find any reference to ways to manipulate string in a shell script. Possibly there aren't any?
Like maybe cut or concatenate or Left or Right?
Any & all help gratefully received.
Douglas JL

A salesman is a machine for turning coke into obnoxious arrogance.

Common sense is what tells you the world is flat.

 

[PHV]

man expr
If in ksh, pay attention at the parameter substitution section of the man page (% and # specials characters within a ${} substitution).

Hope This Help, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884

 

[biot023]

Sorry, I'm rather new at all this.
What I specificaly need to do is get the numerical part of a variable.
say:
VAR1="MAN_193"

I would want VAR2 to be the last three characters of VAR1 so that VAR2=193.
Is that possible?
Or am I asking too much of shell scripting?
Thanks again, man,
DJL

A salesman is a machine for turning coke into obnoxious arrogance.

Common sense is what tells you the world is flat.

 

[PHV]

In ksh:
VAR1="MAN_193"
VAR2=${VAR1#*_}
echo "$VAR2"

Hope This Help, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884

 

[biot023]

Sorry, man - that reported a bad substitution.
Cheers, though.
DJL

A salesman is a machine for turning coke into obnoxious arrogance.

Common sense is what tells you the world is flat.

 

[PHV]

works for me in ksh with copy/paste

Hope This Help, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884

 

[pavNell]

I'm guessing your not using ksh.
Try this...

VAR1="MAN_193"
VAR2=`echo "$VAR1" | sed 's/^*_\(*\)/\1/'`
echo "$VAR2"

this will print anything after the underscore in the string.
not the most efficient or clean. but works!