(standard_in) 1: parse error

[Yarka]

Hi, I've a script as:
...
cat $1 | while read LINE
do
A=`echo "$LINE" | awk -F'\t' '{ print $88 }'`

B=`echo "$A + $B" | tr , . | bc | tr . ,`

done
...

When I execute this, my output is: (standard_in) 1: parse error
I don't know that it is wrong. Can somebody help me?

Thanks

 

[PHV]

What is the ouput produced by the following code ?
cat $1 | while read LINE
do
A=`echo "$LINE" | awk -F'\t' '{ print $88 }'`
echo "$A + $B" | tr , .
done

BTW, what is $B ?

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[Yarka]

Thanks, but B is a variable that contains differents values. For that reason I need to add to the variable B, the current value of B + the value of A

 

[PHV]

Are you aware you didn't answered my first question ?

 

[Yarka]

My output when I execute your code is(Initially B = 00,00000000000):
+ 00.00000000000
+ 00.00000000000
+ 00.00000000000
.....

 

[PHV]

So, seems that your file doesn't have any valid 88th field ...

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[Yarka]

Sorry, I've executed a wrong file. With correct file, my output is:
00.019202000 + 00.000000000
00.102403000 + 00.000000000
00.019548000 + 00.000000000
.................

 

[PHV]

Your output posted 16 Jan 07 18:11 is a perfectly legal input for my flavor of bc ...

 

[Annihilannic]

It looks like you are just trying to add up the values of the 88th field, right? Why not use awk to do everything:

awk '
        { sub(",",".",$88); tot+=$88 }
        END { sub("\\.",",",tot); print tot }
' inputfile

Annihilannic.