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SQL Rank() But move 0 values to bottom of Rank?

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Brianfree

Programmer
Feb 6, 2008
220
GB
Hi, is it possible to rank the Price in ascending order but have all 0 Prices still ranked last? At the moment the 0 Prices are returning as Rank 1 as they are the lowest value?

Example Data

User,Price,Rank
abc,0,5
def,0,5
ghi,1,1
jkl,4,4
mno,5,3
pqr,3,2

Many thanks
Brian
 
What's your SQL to create your outcome?

[pre]
User Price Rank
abc 0 5
def 0 5
ghi 1 1
jkl 4 4
mno 5 3
pqr 3 2
[/pre]
I would just 'fake' another column with my own Price (MyPrice):

[pre]
SELECT
User,
Price,[blue]
CASE WHEN Price = 0 THEN 99
ELSE Price
END As MyPrice[/blue]
RANK () OVER (
ORDER BY [blue]MyPrice[/blue] DESC
) my_rank
FROM
MyTableName;
[/pre]

---- Andy

There is a great need for a sarcasm font.
 
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