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sprintf() not returning expected result

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ppeel

Programmer
Dec 7, 2004
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I have a variable $nfc_amt that I want to add leading zeroes to. The value of $nfc_amt is 115.
my code:
print "NFC_AMT before adding zeroes: $nfc_amt\n";
$nfc_amt = sprintf("%07d", $nfc_amt);
print "NFC_AMT after adding zeroes: $nfc_amt\n";

my result:

NFC_AMT before adding zeroes: 115
NFC_AMT after adding zeroes: 0000114

What am I doing wrong?

Thanks in advance for your help.
 
I imagine it's getting changed somewhere else. If I run the code you posted, I get the following results:
Code:
NFC_AMT before adding zeroes: 115
NFC_AMT after adding zeroes: 0000115
 
Another thought is, are you suing the sprintf statement to do rounding of a floating point number? That could be causing problems.
 
I actually retrieve this number from a DB2 table, and then try to add the leading zeroes.
When I changed the syntax to:
$nfc_amt = sprintf("%07.0f", $nfc_amt);
The Result is correct. So there is something in $nfc_amt that I'm not seeing.
This is a little disconcerting to me. I was comfortable using "%07d" and now I'm not sure it's always working. Out of a file of 6000 records, only 200 were returning the incorrect amount when using "%07d".
 
What is the data type of that field in your database? If you print everything without using printf/sprintf (so, just using print) are the values what you expect (without the leading zeros)?
 
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