Splitting a directory name up with Awk 1

[dendenners]

Hi there,
I have a shell script that takes in a directory name as an argument (e.g. /usr/locl/bin ). The script must check if each individual directory in the argument exists, and if not, it creates it. I was wondering how to get awk to return the left-most directory to 1 variable, (in the above example /usr) and also return the rest of the directory argument to a second variable (in the above example locl/bin) so that I can recurse through the entire argument. Any help would be greatly appreciated.

 

[grega]

Not sure I fully understand your question. Say you want to create the directory structure /dir1/dir2/dir3, and none of those directories exist. The best way to do this is to use mkdir with the -p switch

mkdir -p /dir1/dir2/dir3

This will create all non-existing directories down the path if they don't already exist.

Does this help?

Greg.

 

[dendenners]

Thanks a lot. That's exactly what I wanted.