Specific question regarding Strings 2

[thelordoftherings]

Hello,

Lets say I have a certain String called myString which contains letters, numbers and white spaces.
Can someone please show me how do I find the first occurrence of a character inside the string of a character which represents a number?

 

[sedj]

You could convert the String to an array of chars, and then loop the array, attempting to parse the character to an integer or double.

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[thelordoftherings]

But that's very time cosuming no?

 

[thelordoftherings]

And here is a strange thing:
I tried your method: int in = new Integer(tempArray).intValue(); and it converts all the chrs to int even if the char is not an integer, how could this be?

 

[sedj]

Every char has an int value - so you can't do it like that.
You'd need to do it something like :

try {
  // force the char to a string, and try to parse it
  Double.parseDouble(tempArray[i] +"");
  // it is a number
} catch (NumberFormatException nfe) {
   // not a number
}

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[thelordoftherings]

oh 10x

 

[Diancecht]

Maybe too much time consuming for long Strings

Try this:

String myString = "What1So2Ever";
int len = myString.length;

for (int posFirstDigit = 0;posFirstDigit<len;posFirstDigit++)
  if (Character.isDigit(myString.charAt(posFirstDigit)))
    break;

Cheers,

Dian

 

[ishnid]

Another (probably inferior) alternative, using regexps:

String str = "bfdasf fds 3 fads";
Matcher m = Pattern.compile( "\\d" ).matcher( str );
if ( m.find() ) {
   System.out.println( "First digit is at position: " + m.start() );
}
else {
   System.out.println( "No matches" );
}