Sorting using the 1635-1647th positions

[lmikule]

Looking for a way to sort a file on the 1635-1647th postion of the records. Looking at the Unix sort command it seems as though you have to have some kind of field delimiter. There are no delimiters in this file. Started browsing the AWK forum to see if anything might already have been posted, but didn't find anything. Any help would be greatly appreciated!

 

[flogrr]

lmikule-

Try something like this:

awk 'BEGIN{FS=""} # sets field separator to none

{
NR==1

if (( NR > 1634 ) && ( NR < 1648 )) print

}' your_file | sort > output_file

Hope this helps




flogrr
flogr@yahoo.com

 

[gregor weertman]

Try this.
When # is a char never used in your file so
every line is one record.

sort -t# -b -k 1.1635,1.1647

I never tried it on lines that long.

succes Gregor.Weertman@mailcity.com