sort files by modification time 1

[vlz]

Hi,
I'd like to sort regular files by modification time that resides in directory tree.
Is this command correct?
find /path/to/dir -type f | xargs ls -ltr

Thanks in advance,
Vadim

 

[KenCunningham]

Probably, but it will list the files in date order by directory which might not be exactly what you require?

 

[vlz]

Yes I need files from all dir tree sorted as one list.
Do you have another solution?

 

[Annihilannic]

I disagree, that is the correct command to do this, the only problem however is that if there are enough files to require multiple ls -ltr commands, each of those will be sorted individually.

I was thinking of something like a combination of these two commands to get around that...

[tt]# files older than 6 months
find . -type f | xargs ls -l | awk '!($8 ~ /:/)' | sort -k 8,8n -k 6,6M -k 7,7n > /tmp/sorted
# files newer than 6 months
find . -type f | xargs ls -l | awk '$8 ~ /:/' | sort -k 6,6M -k 7,7n -k 8,8n >> /tmp/sorted[/tt]

... the only problem being that if it was February, for example, you would still have files from the previous year listed with timestamps and they would be sorted incorrectly by the previous command, so it gets complicated...

Annihilannic.

 

[predamarcel]

hi,

If ypu dont have a huge number of files, a command like:
ls -ltr `find /path/to/dir -type f` should work.



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