size of char *

[thides]

How does a char * figure out to be 4? I am using a VC++, and a Windows 98 OS. This is the code:

int main()
{
printf("%d", sizeof(char*));
}

result is 4

int main()
{
printf("%d", sizeof(char));
}

result is 1

char is one byte
char* is 4 bytes.

Could someone please explain the logic?

 

[globos]

char*

is a pointer on char, not a

char

. So sizeof gives the size of a pointer which is 4 on PC architectures.

--
Globos

 

[thides]

OK right I think I remember that... thanks for jogging my memory.