Simple scripting problem - convert `wc -l` to an int

[redsevens]

I'm trying to run a script that will do one of two things, depending on whether or not a directory is empty. The script so far is as follows:

#!/bin/bash
num_sii=`ls /home/sii/incoming/ | wc -l`;
if [$num_sii -eq 0]
then
        echo "There aren't any new files.\n"
else
        echo "There are $num_sii new responses."
        ...
fi

The problem is that $num_sii is a string with leading spaces, and I need to convert that to an integer. This is probably very simple, but I don't know how to do it. Any help would be appreciated!

-Joe

 

[bjverzal]

ls /home/sii/incoming/ | wc -l |awk {'print $1'}

 

[toolkit]

Or:

num_sii=$(expr $(ls /home/sii/incoming | wc -l))
if [ $num_sii -eq 0 ]
then
    echo "There aren't any new files.\n"
else
    echo "There are $num_sii new responses."
    ...
fi

Cheers, Neil

 

[redsevens]

Beautiful! I knew it would be something simple. Thanks!

-Joe

 

[patel]

Hi Red,

#/bin/csh
num_sii=`ls /home/sii/incoming/ | wc -l`;
if [$#num_sii != "0"]

Now It will check wheather it is 0 or >.

Patel

 

[grega]

Or ...

#!/bin/bash
typeset -i num_sii=`ls /home/sii/incoming/ | wc -l`;
if [ $num_sii -eq 0 ]
then
        echo "There aren't any new files.\n"
else
        echo "There are $num_sii new responses."
        ...
fi

Greg.

 

[mohand1]

The best way i think is this

#!/bin/bash
num_sii=`ls /home/sii/incoming/ | wc -l | tr -d ' '`;
if [$num_sii -eq 0]
then
echo "There aren't any new files.\n"
else
echo "There are $num_sii new responses."
...
fi