Simple do-loop in Fortran. Please help !

[260791]

I can't figure out how to make a do-loop in Fortran to do the following:

I have 2 variables. Let's say:

REAL :: level, step

level = 2429.8
step = 1159.8

and I need 10 fields printed out.

The first field will have the value:

level + step
<then the value of the one above + step>
<then the value of the one above + step>
<then the value of the one above + step>
<then the value of the one above + step>
<then the value of the one above + step>
<then the value of the one above + step>
<then the value of the one above + step>
<then the value of the one above + step>
<then the value of the one above + step>

So I'm sure it's simple but I can't figure out how to use the values of variables in do-loops instead of typing the numbers in.

Thanks in advance

 

[NickFort]

Well, you have the variable "level" that has a starting value (2429.8), and on each iteration, you increment it by the value of "step".

So, in the DO loop, you just define:

level = level + step

In each iteration, the previous value of "level" (on the RHS) is incremented by "step", to give the new value of "level" (on the LHS).

Do you need all of the values to be available at the end of the loop (in which case you'll want to store each iteration's values in an array)? You say you just need them printed out, in which case, what I have said should do the trick.

Does that help? Have I understood your question correctly?

--------------------------------------
Background: Chemical engineer, familiar mostly with MATLAB, but now branching out into real programming.

 

[260791]

I get it now !!! Thanks a lot for your help