Should be easy but stuck !!!

[maxcrook]

Currently I run this command in a script to extract data from a log

cat log|tail -150 |grep "Server Window Start"|grep `date +%d-%m-%Y`|grep -v 13-03-2006

I get the following output:
14-03-2006 00:37:36 Server Window Start: 06:00:00 on 14-03-2006
14-03-2006 06:26:06 Server Window Start: 12:00:00 on 14-03-2006

All is well and good apart from I need the first line that is output.However I cant get this as both lines contain (in some format the time starting 06 therefore i cant grep -v 06: in the original command - any ideas ?

 

[p5wizard]

stick a "|head -1" at the back of the command line you already have:
cat log|tail -150 |grep "Server Window Start"|grep `date +%d-%m-%Y`|grep -v 13-03-2006|head -1

or

cat log|tail -150 |grep "Server Window Start *06:"|grep `date +%d-%m-%Y`|grep -v 13-03-2006


HTH,

p5wizard

 

[maxcrook]

er ive just done grep -v 12:00:00 and it works.

Blonde moment I think....

 

[maxcrook]

P5Wizard thanks very much for your help, the way you've done it above is a lot safer than the way ive gone for at least ill catch the first instance each time...
Thanks.

 

[feherke]

Hi

Possible to work only with GNU [tt]grep[/tt] :

-m NUM, --max-count=NUM
Stop reading a file after NUM matching lines.

Feherke.

http://rootshell.be/~feherke/