shell scripts

[djessi]

Hi,
I would like to write to shell scripts :

1) to transform the date from DDMMYY to the standard date
like "fri feb 17 2007"

2) to extract the code of a country from the telephone number and appending that code after or before the number.
Like 33690875643 will give 33690875643 336 (france).
N.B The telephones numbers are stored in a file.

Thanks for help
Djessi

 

[olded]

For #2: Provided the phone number is 1 per line in the file datafile:

!/bin/ksh

while read line
do
   prefix=$(echo "$line"|cut -c 1-3)
   echo $prefix
   var=${line}" "${prefix}
done < data.file
echo "$var"

 

[p5wizard]

It gets more difficult though - some country codes are 1 digit (USA/Canada = 1 NorthAmericanNumberingPlan, Russia = 7) some are 2 digits (France = 33 - not 336, the 6 is an area code, UK = 44) and most are 3 digits (e.g. Luxemburg = 352). There are even 4 digit dialling codes for international satellite phones...


HTH,

p5wizard

 

[olded]

For 1), I'll give you a solution in pieces and all you have to do is build the date string. I'm assuming a date string in the format:

mydate="DDMMYY"

First, you need an algorithm for returning a day of the week from a date:

#!/bin/ksh

# this function returns the day of week where
# $1 - month
# $2 - day
# $3 - year
# from Mike Keith's
# [URL unfurl="true"]http://users.aol.com/s6sj7gt/mikecal.htm[/URL]
# returns 0=Sun, 1=Mon, etc
get_dow ()
{
# [x] means to truncate downward to the nearest integer
# dayofweek = ( [23m/9] + d + 4 + y + [z/4] - [z/100] + [z/400] - 2 (if m >= 3) ) mod 7
typeset -i DOW
typeset -i z
typeset -i multpr

if [ $1 -lt 3 ]
then # year determination
   z=$(($3-1))
else
   z=$3
fi
if [ $1 -ge 3 ]
then # set the multiplier
   multpr=2
else
   multpr=0
fi
DOW=$(( ((23 * $1/9) + $2 + 4 + $3 + ($z/4) - ($z/100) + ($z/400) - $multpr) % 7))

echo $DOW
}

Define the variables and call the function:

typeset -i mm
typeset -i dd
typeset -i yy

mydate="160207" # Feb 16, 2007, a Friday
# cut out the day, month, and year
dd=$(echo $mydate|cut -c 1-2)
mm=$(echo $mydate|cut -c 3-4)
yy=$(echo $mydate|cut -c 5-6)
#only dates past 2000
((yy+=2000))

# get day of the week, 0-6
# MAKE SURE DATE IS YYYY FORMAT
dow=$(get_dow $mm $dd $yy)

Determine the day string:

case $dow in
   0) day="Sun";;
   1) day="Mon";;
   2) day="Tues";;
   3) day="Wed";;
   4) day="Thurs";;
   5) day="Fri";;
   6) day="Sat";;
   *) day="error";;
esac

Determine the month string:

case $mm in
   1) month="Jan";;
   2) month="Feb";;
   3) month="Mar";;
   4) month="Apr";;
   5) month="May";;
   6) month="Jun";;
   7) month="Jul";;
   8) month="Aug";;
   9) month="Sep";;
  10) month="Oct";;
  11) month="Nov";;
  12) month="Dec";;
   *) month="error";;
esac

That should be all you need to build your date string

 

[djessi]

Thanks for your answers.
It's true the difficulty for code extraction is the fact that code lenghts are not the same.