Sets in Python 2.4.2

[eamc]

In Pyton 2.4.2, set1=set(['abracadabra']) results in 'abracadabra' as a member, while set2=set('abracadabra') results in 'a' 'r' 'b' 'c' as members. How do I get the input from a raw_input query into a set1 type set? How should the input be made?

Edwin M.

 

[ericbrunson]

A string is a special case of a sequence. Since set expects a sequence as its argument, it splits it into component elements. The first example you gave, since the argument is a sequence containing a sequence is the correct way to accomplish what you want.

As a side note, if you'd tried you second example passing in a number instead of a string (which is a sequence) you would have gotten an exception indicating that a sequence is required.

 

[ProblemSolver]

eamc,

set1 has a list as it's basic element - so if you want to get a string entered by the user in response to a raw_input, this may be the way to go:

set1 = set([raw_input("What's the magic word?: ")])

Unfortunately, I don't have 2.4 installed (yet) so can't verify this, but if the above doesn't work, the solution below is bound to:

x = [raw_input("What's the magic word?: ")]
set1 = set(x)

Hope this helps,

- Problemsolver