SED , trying to extract data by the given range 1

[alibaba786]

Hi,
I am trying to extract data from the log files by the given date range.

for example:
extract info 2009-02-17 08:02:16 to 2009-02-17 14:50:40

2009-02-17 08:02:16> [INFO] Shutdown Init pin is set
2009-02-17 08:02:16> [INFO] 2009-02-17 09:02:16.4428
2009-02-17 08:02:16> [INFO] Shutdown process started
2009-02-17 08:02:16> [INFO] Shutdown appended to /var/opt
2009-02-17 08:02:16> [INFO] Logfile moved to /var/opt
2009-02-17 08:02:16> [INFO] Prepare for shutdown Tue Feb 17
2009-02-18 14:50:40> [INFO] Start of Ocean on ocean5476
2009-02-18 14:50:40> [INFO] =
2009-02-18 14:50:40> [INFO] System version 6.2.0.26
2009-02-18 14:50:40> [INFO] HW version 2.4
2009-02-18 14:50:40> [INFO] Ocean version 5.6.5
...


Here you can notice, date is variable in each line

Can someone help me in this regard

 

[johngiggs]

alibaba786,

How about using awk?

awk '/^2009-02-17 08:02:16/,/2009-02-17 14:50:40/' testfile

Hope that helps.

John

 

[SamBones]

Sed works too...

sed -n '/^2009-02-17 08:02:16/,/^2009-02-17 14:50:40/p' testfile

 

[alibaba786]

Thanks a lot , it works