sed substitution within bash script with mixed quotes

[admoore]

I am trying to update some legacy php code via some sed substitutions running in a bash script.
Some items seem to work fine; others not so much. The issue appears to be when the substitution strings contain single or double quotes.
I have tried a variety of means of escaping the quotes; but, have had no success.
Here is an example line from my bash script:

[pre]/usr/bin/sed -i 's/(session_is_registered('ADMIN')/$_SESSION["group_code"]=='ADMIN'/g' /home/impact/php_repair_temp/*.php[/pre]

I wish to replace: session_is_registered('ADMIN')
With: $_SESSION["group_code"]=='ADMIN'

Other substitutions without quotes in the string are working fine...

TIA,
-Allen M.

 

[feherke]

Hi

/usr/bin/sed -i 's/(session_is_registered('"'"'ADMIN'"'"')/$_SESSION["group_code"]=='"'"'ADMIN'"'"'/g' /home/impact/php_repair_temp/*.php

Alternatively you can just move the Sed code to a Sed script file to avoid shell quoting problems :

/usr/bin/sed -i -f transform-my-code.sed /home/impact/php_repair_temp/*.php

s/(session_is_registered('ADMIN')/$_SESSION["group_code"]=='ADMIN'/g

Feherke.
feherke.github.io