SED - Search for a letter replace with a carriage return

[keusch]

I have a script that reads a file and one of 20 steps should search for a "D" and replace the "D" with a carriage return. What would be the command to do this subsitution.
Right now I'm getting to this point and take the file into VI run a macro then start the next script. Any suggestions to do it in one step?
input
17597947.53 1954112.92D 17597947.53 1954098.27D 17597496.95 1953010.46D 17596664.38 1952177.89D 17595576.57 1951727.31D 17594399.15 1951727.31
17593311.34 1952177.89D 17592478.77 1953010.46D 17592028.19 1954098.27D 17592028.19 1955275.69D 17592478.77 1956363.50D

desired output
17597947.53 1954112.92
17597947.53 1954098.27
17597496.95 1953010.46
17596664.38 1952177.89
17595576.57 1951727.31
17594399.15 1951727.31
17593311.34 1952177.89
17592478.77 1953010.46
17592028.19 1954098.27
17592028.19 1955275.69
17592478.77 1956363.50

Thanks

 

[vgersh99]

tr 'D' '\n' < file.txt vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[vgersh99]

a bit better:
tr 'D' '\n' < file.txt | sed 's/^ *//g'


and after all it's an AWK forum:
nawk 'BEGIN {RS=&quot;D&quot;} {gsub(&quot;^ *&quot;, &quot;&quot;print}' file.txt vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[keusch]

This part of the script reads:
sed '
{
s/D/\n/g
}
' 1.txt > 2.txt
which does not work. Is that what you were suggesting??
Please advise.

 

[keusch]

OK - the 1st suggestion work just fine - I was just a tad braindead.
Thanks for the info!!

 

[bigoldbulldog]

for sed try out

sed '
s/D//g
' 1.txt > 2.txt

or if you don't use the hold space you could do something wierd, slow, but occasionally handy -

sed '
/D/{
G
:a
s/\(.*\)D\(.*\)\(\n\)/\1\3\2\3/
t a
s/\n$//
}
' 1.txt > 2.txt

The /D/ is there to skip lines that don't need to be processed. The :a label with t starts recurses the line until all D's are replaced with new lines. The last substitution removes the extraneous newline.

P.S. when you say carriage return I assume you mean a new line or 0A-line feed character not 0D-carriage return in the DOS sense. Cheers,
ND

bigoldbulldog@hotmail.com

 

[keusch]

bigoldbulldog,
regarding your P.S., yes carriage return = new line (like a typewriter or perhap's that too dated for most users tuning in)
As for yur second suggestion - that's certainly a learning exercize. I'll try to digest that one.
Thanks for the tip!