Sed - From ^ to the first occurrence 1

[sumncguy]

I want to isolate the ip. How do I get sed to delete from the start of the line (^) up to and including the first period ?

52.10.206.137.156
52.10.211.16.3
52.10.213.35.1

checked Oreilly Sed and Awk Pocket ref and some cheets I hold ....

Thanks

 

[sumncguy]

sed '0,/RE/s//to_that/' file # change only the first match
Doesnt work ...

 

[sumncguy]

's/[^*\.]*/ /1'
.10.206.137.156
.10.211.16.3
.10.213.35.1
.10.213.35.4
.10.213.35.10
.10.218.253.19
.146.170.71.103

Gettin there ...

 

[PHV]

And what about this ?
sed 's!^[^\.]*\.!!' /path/to/input > output

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[sumncguy]

Works great .... Thanks .. but like to understand what Im using ...

^ = line starts with
[] = match one from a set
* = match zero or one preceding
\ = literal

I just dont see how to read it ...

 

[feherke]

Hi

* = match zero or one preceding

Actually, it is zero or more. The question mark ( ? ) means zero or one.

Feherke.

http://rootshell.be/~feherke/