search function

[Fumac]

Hi,

I wonder how to use search().
My problem is that I have an URL to a picture, but want to know if the choosen picture is jpeg or gif format. Maby there´s a easier way to do this.
The URL comes from an '<input type=file ...>'.

Thank you for any respons

/Fumac

 

[AndrewGrabovsky]

If you have an URL to a picture, you have it's extention also.
Specify exactly what the problem is.

Andrew | starway@mail.com

 

[Fumac]

Hello Andrew,
The url comes from an input used for uploading images, and every time someone uploads an image, i want to know it´s extention.
My problem is that i don´t know how to pick out this little piece of information from the string using javascript.

I hope this helps you understand what i mean.

/Fumac

 

[AndrewGrabovsky]

OK, now I understand. It's very easy.
Let's say, you have a form element named FIELD1, from which you get filenames.
In order to receive file extentions you have to get last 3 chars of a string:

filename = document.forms[0].field1.value;
ext = filename.substring(filename.length-3, filename.length);

You may also write it as one expressin if you want:

ext = document.forms[0].field1.value.substring(document.forms[0].field1.value.length-3, document.forms[0].field1.value.length)

where
document.forms[0].field1.value - total filename string
document.forms[0].field1.value.length - number of characters in it

we use Substring() function to get only the chars we need. In our case - last three ones.
It works everywhere - IE, NN, Opera.
Enjoy!

Andrew | starway@mail.com

P.S. I just recalled that some files have 4-char extention, with .JPEG being one of them. Maybe you should check it too.

 

[Fumac]

Thank you Andrew, I´ll try to solve that problem...(them 4 digits).
It´s much easier now when I know how to work.

Thank you

/Fumac