Script will not be executed without the -w flag ?!

[shlomyb]

Hi guys

I have a script named "a.pl"

1.I can NOT execute it with the following command : perl a.pl
and I get the following command :" bad interpreter: No such file or directory"

2.But CAN with : perl -w a.pl

I use a linux machine and verified by a "which perl" command the perl path (/usr/bin/perl)

 

[mbrooks]

The first line of your script should contain.

#!/usr/bin/perl

M. Brooks

http://mbrooks.info

 

[mbrooks]

Also, you can execute a perl script like

% ./a.pl

M. Brooks

http://mbrooks.info

 

[shlomyb]

Thanks ,but I know that and it has ....

 

[stevexff]

I've seen the shebang line coded as

#!/usr/bin/perl -w

before, but I don't know if it has any effect. Then you might be able to

./a.pl

as mbrooks suggests?

Steve

[small]"Every program can be reduced by one instruction, and every program has at least one bug. Therefore, any program can be reduced to one instruction which doesn't work." (Object:erlDesignPatterns)[/small]

 

[Kirsle]

I've had website hosting on linux servers, and one of them required the "-w" switch on the shebang line, otherwise we'd get a 500 Internal Server Error.

So the first line of code had to look like this:

#!/usr/bin/perl -w

Because without the -w, the code wouldn't run.

-------------
Cuvou.com | The NEW Kirsle.net

 

[spookie]

Hi Kirsle ,
Where it can be defined that perl script will run only when particular switch is used?


--------------------------------------------------------------------------
I never set a goal because u never know whats going to happen tommorow.