script using awk and sed

[ryanildo]

I am creating a script that will enter a file (XYZ) and verify that a list of files (ABC) within the file (XYZ) have a certain number of fields. Specifically, I am checking to see that the listed files have nine fields and are separated by a semi-colon ; delimiter. Here is what I have so far. I need help creating part of the script that echoes the line number of any file that isn't 9 fields long or that doesn't have a semi-colon as a delimiter. Can anyone help?

BEGIN{
FS=";"
}

{
if ( NF != 9)
{
printf("%s\n", $0)
}
else
{
printf("%s\n", "The line is complete&quot
}

}

Any help would be much appreciated.

Thanks

 

[vgersh99]

BEGIN{
FS=";"
}

NF != 9 {
printf("%s : %d\n", FILENAME, FNR);
} vlad
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