Script to break file into 80 char recs 1

[ls62]

Hi,

I have a text file that has no newlines in it and I want to break it into 80 character records with newlines after every 80 chars. I know there's a command to easily do this, but can't remember. I thought it was 'dd' but can't seem to figure syntax out.

Can anyone help?

Thanks.

LEE

 

[vgersh99]

man fold

 

[ls62]

Thank you, thats the command I needed! I knew someone would know right away.

Again. Thanks

 

[ls62]

Ok... I should have asked this before. I receive a file in 80 char blocks with some character as the record separator. Is there a command to remove the 81st character. I know I could use 'tr' to delete that character if I new what it was, but what if it was variable... what command could I use?

Thanks

LEE

 

[vgersh99]

pls provide a sample input AND a sample output. It'll make it easier to understand the objective.

vlad

 

[ls62]

In this particular case I have records with 80 characters and then a n/l. I want to strip out the n/l. Generally speaking that n/l character could be any (ie bell, ack, ~) character.

 

[vgersh99]

try:

cut -c1-80 file

 

[ls62]

Sorry, the cut command doesn't work because it outputs a n/l after each 'cut' line is outputted.

If I cut -c1-40 ,for example, I get 40chars then n/l.

Thanks.

 

[olded]

ls62:

The problem is not with the cut command; it's probably with whatever your output command is. If you're using Korn Shell, use the printf command:

printf("%s", "123&quot

prints string "123" with no new-line.

If you don't have ksh, use awk:

echo "123"|awk ' { printf("%s", $0) } '

Regards,

Ed