Script for find plex in Symmetrix

[Currando]

Hello all;

I have a problem with a script in AWK, I need find two ocurrences in a piece of exit of a command. When I run the command "vxprint -Aht" the exit of the command is similar to this:

v ofiu03-L02
pl ofiu03-P03
sd d64t0-02
pl ofiu03-P04
sd d64t1-02

v ofiu03-L03
pl ofiu03-P05
sd d65t0-02
pl ofiu03-P06
sd d65t1-02

v ofiu04
pl ofiu04-04
sv ofiu04-S03
sv ofiu04-S04

v ofiu04-L03
pl ofiu04-P05
sd d66t0-02
pl ofiu04-P06
sd d66d1-02

The first that I need is separate each of the volume (a volume start with the letter "v" in the first field and end with white line) once separate each of this volumen, I need know which of this have two or more lines with "pl" in the first field. For each of this volume that have two or more "pl" I need that the script show me which volume name is (but this is not important).

Can anybody help me please, I have a very big problem in my job for this.

Thanks in advance for your time

Regards

Currando

 

[vgersh99]

this might be a start:

nawk -f plex.awk plex.txt

#------------------ plex.awk
$1 == "v" {
if (plNum > 1)
printf("Multiple pl's for v=[%s]\n", vValue);
vValue=$2
plNum=0;
next;
}

$1 == "pl" { plNum++ }

END {
if (plNum > 1)
printf("Multiple pl's for v=[%s]\n", vValue);
}
vlad
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