SBS 2003 and CALs

[stevescottys]

Here is the situation

I have Small Business Server 2003 all updated with Exchange 2003.

I have 14 Users and 15 Cals.

I am getting tons of errors about licensing. If I log in as the administrator I can't do anything because there are not enought Cals.....

1)Is there some way that I can see how many Cals are being used?
2)If a user has been disabled do they still take up a CAL?

This issue is starting to screw everything up...and help would be appreciated.

 

[Mike555]

Check your CALS by clicking on Start, Server Management. From here open Liscensing, and you will be able to view Installed licenses and Maximum Usage (which is the number of liscenes currently being utilized).

--
Mike

 

[stevescottys]

Actually thats incorrect...the installed licences in the licensing window are the licences that were installed with OS...if you have SBS 2003 you get 5 Cal installed....hence it would say 5 installed and 12 maximum usage (you are correct with this statement).

I have however solved the problem.....it had to do with license Logging service....according to Microsoft this feature doesn't work right....it logs Cal per user not per machine......ie if 2 users log with the same machine it uses 2 cals. If you turn the service off it solves the problem.

Thanks

 

[andymac3000]

Guys, ive recentely set up an sbs 2003 standard edition with an additional 10 user cals, making it a total of 15.

The Maximum usage at the moment is showing as 13, but im not that confident about how the licencing works in sbs, even after reading the eula. I wonder if anyone could answer the following

If we setup additional users and mailboxes, but the mailboxes are used as resource mailboxes (i.e. no one logs on to them after they are setup, they just receive mail and users have permissions to view them) would that use up a cal.

Also does the licencing work concurrently, the eula talks about having to revoke licenses for users, but am i right in thinking if a user logs off, then that connection is freed up ?

Thanks for any help

Andy