return line above pattern 1

[caltman]

I have a file (test.log) that contains the string: TOTAL_MEMBERS in various places. I need to get a listing of the line that is always two lines above this string, but my version of grep apparently doesn't support the -C flag. Is there a way to get the information that I need?

Example of file data:
...
14:47:27.400: VALUE="10"
14:47:27.400: TYPE="STRING"
14:47:27.400: NAME="TOTAL_MEMBERS"
...
14:47:27.572: VALUE="23"
14:47:27.572: TYPE="STRING"
14:47:27.572: NAME="TOTAL_MEMBERS"
...


This should return:
14:47:27.400: VALUE="10"
14:47:27.572: VALUE="23"

Any help is appreciated.

Coley

 

[PHV]

Try something like this:

awk '
/TOTAL_MEMBERS/{print a[NR%2]}
{a[NR%2]=$0}
' test.log

Hope This Help
PH.

 

[caltman]

Thanks - figured it would be simple. There's your star.

Coley