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Return Characters to left of final dash in an address 2

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Moss100

Technical User
Aug 10, 2004
579
0
16
GB
Hello I am trying to clean up an address field.

The addresses are in one field (Address1) and typically have a format of:

11 White Street - Ft1 - Konopka
28 Brown Road - Smith

I basically want to separate the address from the name.

So in a query I would like:

1. A field with all the text on the left of the last "-"
2. A field with all the text on the right of the last "-"

To solve requirement 1, I have tried:

Code:
AddressOnly: Left([Address1],InStr([Address1],"-")-1)

But this does not work where there is more than one "-"

Many thanks Mark

 
Hi,

I'd write a user defined VBA Function...
Code:
Function SubStr(sValue, sChr, sFLNum)
'sValue: the string you want to parse
'sChr: the delimiter character
'sFLNum: F first, L last Number any number from 1 to the max number of delimiter character

    Select Case sFLNum
        Case "F"
            SubStr = Split(sValue, sChr)(0)
        Case "L"
            SubStr = Split(sValue, sChr)(UBound(Split(sValue, sChr)))
        Case Else
            If IsNumeric(sFLNum) Then
                SubStr = Split(sValue, sChr)(Val(sFLNum) - 1)
            End If
    End Select
    SubStr = Trim(SubStr)
End Function

Skip,
[sub]
[glasses]Just traded in my OLD subtlety...
for a NUance![tongue][/sub]
 
You could also flip your string (Address1) which will give you the name first, parse it, and flip it back [spin2]

Code:
Sub test()

Dim sA As String
Dim sRev As String

sA = "11 White Street - Ft1 - Konopka"[green]
'sA = "Brown Road - Smith"[/green]

sRev = StrReverse(sA)

Debug.Print "Address is: " & Replace(sA, " - " & Trim(StrReverse(Split(sRev, "-")(0))), "")
Debug.Print "Name is: " & Trim(StrReverse(Split(sRev, "-")(0)))

End Sub


---- Andy

There is a great need for a sarcasm font.
 
And just for fun with regular expressions:

Code:
[blue]Public Sub example()
    Dim sA As String
    sA = "11 White Street - Ft1 - Konopka"
    
    With CreateObject("vbscript.regexp")
        .Pattern = "(.*) - (.*$)"
         If .Test(sA) Then
            With .Execute(sA).Item(0)
                Debug.Print "Address is: " & .SubMatches(0)
                Debug.Print "Name is: " & .SubMatches(1)
            End With
        End If
    End With

End Sub[/blue]
 
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