resolving template conflict?

mashadt · Jul 4, 2005

in my XML I have a <chapter> root element. In this I have an <exercise> element and an <explanation> element. Each of these have child elements <heading> and <content>

I want my XSLT style sheet to process the heading and content elements the same regardless of where they are.

Ive done it by creating a template for //heading and //content.

But if I create anoter template for a parent of either of these, ( for exercise or explanation) then it overrides the earlier templates. How can I avoid this? I've tried assigning priorities but cant seem to get it right.

<xsl:template match="/">
<html>
<head>
<title>This is my first real try</title>
<link rel="stylesheet" href="try.css"/>

</head>
<body>

<h1>Chapter One</h1>
<xsl:apply-templates select="/chapter" />

</body>
</html>
</xsl:template>

<xsl:template match="//heading" >
<h2><xsl:apply-templates select="text()"/></h2>

</xsl:template>

<xsl:template match="//content" >

<xsl:apply-templates select="text()"/>
</xsl:template>



<xsl:template match="instruction" >
<ul>
<li>

<xsl:if test="step">
<b>hello</b>
</xsl:if>
<xsl:apply-templates select="text()"/>
</li>
</ul>

</xsl:template>

</xsl:stylesheet>

JontyMC · Jul 4, 2005

How about this:

Code:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="[URL unfurl="true"]http://www.w3.org/1999/XSL/Transform">[/URL]
  <xsl:template match="/">
    <html>
      <head>
        <title>This is my first real try</title>
        <link rel="stylesheet" href="try.css"/>
      </head>
      <body>
        <h1>Chapter One</h1>
        <xsl:apply-templates/>
      </body>
    </html>
  </xsl:template>
  <xsl:template match="heading">
    <h2>
      <xsl:apply-templates/>
    </h2>
  </xsl:template>
  <xsl:template match="content">
    <xsl:apply-templates/>
  </xsl:template>
  <xsl:template match="explanation">
    <xsl:if test="solution">
      <b>this is the solution</b>
    </xsl:if>
    <xsl:apply-templates/>
  </xsl:template>
  <xsl:template match="instruction">
    <ul>
      <li>
        <xsl:if test="step">
          <b>hello</b>
        </xsl:if>
        <xsl:apply-templates/>
      </li>
    </ul>
  </xsl:template>
</xsl:stylesheet>

Jon

"Asteroids do not concern me, Admiral. I want that ship, not excuses.

mashadt · Jul 4, 2005

Ah HAH!

So I geuss

<xsl:apply-templates select="text()"/>

is redundant? I can just say

<xsl:apply-templates/>

unless I want to target some other node.

Thanks - learning this stuff by myself is very much a "one step forward three steps back" affair.

JontyMC · Jul 5, 2005

The default template is:

Code:

<xsl:template>
  <xsl:value-of select="."/>
</xsl:template>

So if you don't specify a template for a node, it will output the text.

Jon

"Asteroids do not concern me, Admiral. I want that ship, not excuses.

mashadt · Jul 5, 2005

OK - still on the same topic. Now I'm trying to sort the elements. I would like to be able to have the <explanation> elements appear alphabetically according to the content of their <heading> child elements.

I've commented out my various attempts, each version of which gives me something I dont quite understand. The first try makes the last element (<instruction>) appear first? Why would that happen?

I think I understand why the second attempt makes everything else dissapear. There is a conflict in the templates there.

And the final one obviously does not work. So what is the answer here?

<xsl:template match="/">
<html>
<head>
<title>This is my first real try</title>
<link rel="stylesheet" href="try.css"/>

</head>
<body>
<h1>Chapter One</h1>

<xsl:apply-templates/>

</body>
</html>

</xsl:template>




<xsl:template match="heading">
<h2>
<xsl:apply-templates/>
</h2>
</xsl:template>

<xsl:template match="content">
<p><xsl:apply-templates/></p>
</xsl:template>



<xsl:template match="explanation">
This is the explanation template
<xsl:apply-templates/>
</xsl:template>

<xsl:template match="instruction">
<ul>
<li>
<xsl:if test="step">
<b>hello</b>
</xsl:if>
<xsl:apply-templates/>
</li>
</ul>
</xsl:template>

</xsl:stylesheet>

Cant remember if I've changed the XML. Its
<chapter>
<explanation listing="2">
<heading>Explanation heading</heading>
<content>aFirst ExplanationCONTENT</content>
</explanation>
<explanation listing="1">
<heading>aSecond Explanation heading</heading>
<content>Second Explanations Content</content>
<solution>aExplanation Solution</solution>
</explanation>
<exercise>
<heading>Exercise heading</heading>
<content>Exercise Content</content>
</exercise>
<instruction>
<step>steps</step>instruction1</instruction>
<instruction>instruction2</instruction>
</chapter>

JontyMC · Jul 5, 2005

Instuction appears first because you're sorting all the nodes under chapter by heading. It doesn't find a value for heading for instruction, so I guess the sort algorithm puts that first.

Try this:

Code:

  <xsl:template match="/">
    <html>
      <head>
        <title>This is my first real try</title>
        <link rel="stylesheet" href="try.css"/>
      </head>
      <body>
        <h1>Chapter One</h1>
        <xsl:apply-templates select="chapter/explanation">
          <xsl:sort select="heading"/>
        </xsl:apply-templates>
        <xsl:apply-templates select="chapter/exercise"/>
        <xsl:apply-templates select="chapter/instruction"/>
      </body>
    </html>
  </xsl:template>

Jon

"Asteroids do not concern me, Admiral. I want that ship, not excuses.

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resolving template conflict?

mashadt

Instructor

JontyMC

Programmer

mashadt

Instructor

JontyMC

Programmer

mashadt

Instructor

JontyMC

Programmer

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