replace specific line of files with "some expression"

[starlite79]

Hi,

I have some webpages that I built using a template. The first 38 lines of each html file are the same. I'd like to use Perl to change line 38 to say <div id = "body" class="clearfix"> (It currently is <div id="body">)

I was thinking of trying this:

perl -ple '$_ = "<div id=\"body"\ class=\"clearfix"\>" if $. == 38; close ARGV if eof' *.html

Is the syntax right for using literal quotes and such?

 

[Annihilannic]

Did you mean to use -pie?

You need to put your escapes (i.e. backslashes) before each double-quote... not surround them in backslashes. e.g. id=\"body\" instead of id=\"body"\. Backslash always escapes the character immediately following it.

Annihilannic.

 

[feherke]

Hi

change line 38 to say <div id = "body" class="clearfix"> (It currently is <div id="body">)

[tt][small][blue][ignore][off-topic][/ignore][/blue][/small][/tt]
I would just copy the .clearfix rules into the #body style definition in the CSS.
[tt][small][blue][ignore][/off-topic][/ignore][/blue][/small][/tt]

Did you mean to use -pie?

If yes, he probably means -pi -e.

Feherke.

http://free.rootshell.be/~feherke/

 

[starlite79]

Thanks for the help. Sorry for the late response, but I was away from my computer for a week.

This seemed to do what I wanted (I wanted to replace line 38)

perl -i -ple '$_ = "<div id=\"body\" class=\"clearfix\">" if $. == 38; close ARGV if eof' *.html

It's actually what she meant; just to clarify