Replace in XSL 1

[woohahee]

Ok I have this small problem which is really doing my head in - I have an address which is set up basically like:

<ADDRESS>TEST,TEST,TEST</ADDRESS>

Now all I want to do is replace the comma with <BR/>

My code so far is:

<xsl:for-each select=&quot;ADDRESS/ADDRESSLINE[. != '']&quot;>
<xsl:value-of select=&quot;.&quot;/><BR/>
</xsl:for-each>

Is there any expression I can use?

<xsl:value-of select=&quot;expression(.,',','<BR/>')&quot;/>
<BR/>

Please help,

Richard

 

[flumpy]

no. at first I thought translate(exp1, delim1, replacementstr) might have helped, but not this time. it seems to only replace however many characters you specify in delim1, and ignores the rest of replacementstr. ho hum.

you are either going to have to follow this persons advice:

http://lists.fourthought.com/pipermail/exslt/2001-April/000032.html

or extend the functionality of xpath with a scripting language (msxml only so far i think):

http://msdn.microsoft.com/library/default.asp?url=/library/en-us/xmlsdk/htm/xsl_elm_qz_4s50.asp

hope that helps.

mattc

 

[woohahee]

Yeah thanks for your quick reply - I also found this which is similiar:

http://aspn.activestate.com/ASPN/Cookbook/XSLT/Recipe/65426

Cheers,
Richard