replace an element from a list

[mune77]

I got a list,
frq 1 1 1 1 1 2 2 3 ...,
I need to to change the 3rd ELEMENT which is 1, to 5.
I know the "lreplace" command wouldn't work for this as it doen't take the index of the list.

Is there a command to do this job?
if not, the possibility might be deleting the 3rd element and appending the new value.
Is there a command to delete a value from a list if the index is given?

Thanks in advance!

 

[feherke]

Hi

I know the "lreplace" command wouldn't work for this as it doen't take the index of the list.

Are you sure ?

[b]set[/b] frq [teal][[/teal][b]list[/b] a b c d e f[teal]][/teal]

[b]puts[/b] [navy]$frq[/navy]

[b]set[/b] frq [teal][[/teal][b]lreplace[/b] [navy]$frq[/navy] [purple]2[/purple] [purple]2[/purple] x[teal]][/teal]

[b]puts[/b] [navy]$frq[/navy]

[b]lset[/b] frq [purple]2[/purple] y

[b]puts[/b] [navy]$frq[/navy]

a b c d e f
a b x d e f
a b y d e f

I would say [tt]lreplace[/tt] does it. But [tt]lset[/tt] looks like a more appropriate solution.

Feherke.

http://rootshell.be/~feherke/

 

[mune77]

damn!!
you are a genius!
thanks feherke