Repacing a string in only 1 column

[lbzh]

I have a file and I wish to replace a specific column if it contains a value to another value

An example is below:

Input file

222222
121111
323333

I wish to replace the "2" in the 2nd column to a "9" , all other columns remain intact, so the output looks like this:

299999
191111
393333

Thanks

 

[vgersh99]

sed -e 's/^\(.\).\(.*\)/\19\2/g' myFile

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[PHV]

A starting point:
sed 's!^\(.\)2!\19!' /path/to/input > output

Hope This Helps, PH.
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