Removing words in a file.

[tijerina]

Can somebody help me? New to unix and trying to remove certain letters in a file. Can a script do this? For example, a logfile has the first three letters of each month as part of a time stamp. I would like a script to remove the first three letters of every month, ie.. Jan, Feb, Mar, Apr, etc.

How can I do this? Grep? Awk? Sort?

Thank you.

Chris

 

[vgersh99]

a sample file, pls!

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[tijerina]

Here is a sample and thank you.


Dec 30 15:44:27 localhooo sendmail[3213473]: hBUKiPf33213473: to=MICH.ACCT-ASA.8
98U04@COMPANY.COM, ctladdr=MGR.OONNN (142/121), delay=00:00:02, xdelay=00:0
0:02, mailer=relay, pri=30128, relay=localhooo [111.11.111.1], dsn=2.0.0, ooat=Sent
(hBUKiQAQ1901345 Message accepted for delivery)
Dec 30 15:44:27 localhooo sendmail[3409186]: hBUKiQAQ1901345: to=<MICH.ACCT-ASA.
898U04@COMPANY.COM>, ctladdr=<MGR.OONNN@xxx0500.company.com> (142/121),
delay=00:00:01, xdelay=00:00:00, mailer=esmtp, pri=120923, relay=ms00net2.opr.oo
ateooo.org. [11.11.11.86], dsn=2.0.0, ooat=Sent (OAA25528 Message accepted for
delivery)
Dec 30 16:07:05 localhooo sendmail[2033007]: hBUL756x2033007: from=MGR.OONNN,
size=885, class=0, nrcpts=1, msgid=<200312302107.hBUL756x2033007@xxx0500.ooate
ooo.com>, relay=MGR.OONNN@localhooo
Dec 30 16:07:06 localhooo sendmail[3541224]: hBUL76AQ3541224: from=<MGR.OONNN
@xxx0500.company.com>, size=885, class=0, nrcpts=1, msgid=<200312302107.hBUL7
56x2033007@xxx0500.company.com>, proto=ESMTP, daemon=MTA, relay=localhooo [12
7.0.0.1]
Dec 30 16:07:07 localhooo sendmail[2033007]: hBUL756x2033007: to=ROB.OOOOO.BBZ
0@COMPANY.COM, ctladdr=MGR.OONNN (142/121), delay=00:00:02, xdelay=00:00:02
, mailer=relay, pri=30114, relay=localhooo [111.11.111.1], dsn=2.0.0, ooat=Sent (hB
UL76AQ3541224 Message accepted for delivery)
Dec 30 16:07:07 localhooo sendmail[3735627]: hBUL76AQ3541224: to=<ROB.OOOOO.BB
Z0@COMPANY.COM>, ctladdr=<MGR.OONNN@xxx0500.company.com> (142/121), dela
y=00:00:01, xdelay=00:00:00, mailer=esmtp, pri=121267, relay=ms00net2.opr.ooatef
vvv.org. [11.11.11.86], dsn=2.0.0, ooat=Sent (PAA00866 Message accepted for del
ivery)

 

[vgersh99]

depending on how well-behaved your data is:

sed -e 's/^...//g' myFile

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[PHV]

An awk way:

awk '
/^(Jan|Feb|...|Nov|Dec) /{
 print substr($0,5);next
}
{print}
' /path/to/inputfile >outputfile

Hope This Help
PH.

 

[PC888]

Tigerina,
I have two questions to clarify what you're trying to do:
1. Do all of your lines start with a three letter month name? It is not obvious because of the formatting after the post.
2. Do you really want to remove three characters, thus leaving a blank space at the beginning of the new lines, or do you want to remove that space as well?
Thank you.