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Removing #Fault , #Error from access sql query expression

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Crunchy1234321

Crunchy1234321

Programmer
Jul 2, 2012
1
thread703-1248315

IIf([Quantity]=0,0,[Price]/[Quantity])
This helped but I needed to change the "," with as ";"
so the final expression is

IIf([Quantity]=0;0;[Price]/[Quantity])



 
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