im trying to use the GET command on to find my public address then pipe it to awk to show only the address can anyone tell me the command(s) to remove the last 14 charaters from field 6
Thanks
Thanks
Tek-Tips is the largest IT community on the Internet today!
Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!
-
Congratulations gkittelson on being selected by the Tek-Tips community for having the most helpful posts in the forums last week. Way to Go!
removing charaters
- Thread starter zypher74
- Start date
I'm not familiar with GET, but this gets the last 14 characters of field 6. Using nawk for solaris:
Code:
#!/bin/ksh
gline="1 2 3 4 5 Xab12345678901234 seven eight"
estr=$(echo "$gline"|nawk ' { print substr($6, (length($6)-13)) } ')
echo "$estr"Hi:
I may have misinterpreted what you asked for. If you want to remove the last 14 characters of field 6 and save everything else:
I may have misinterpreted what you asked for. If you want to remove the last 14 characters of field 6 and save everything else:
Code:
#!/bin/ksh
gline="1 2 3 4 5 Xab12345678901234 seven eight"
echo "$gline"|nawk ' { gsub(/..............$/, "", $6); print $0 } '- Thread starter
- #4
- Thread starter
- #5
- Thread starter
- #6
hate to keep replying to my own thread but
here is what i came up with
GET | awk ' { gsub(/...............$/, "", $6); print $6 } '
any better way ??
here is what i came up with
GET | awk ' { gsub(/...............$/, "", $6); print $6 } '
any better way ??
You may try this:
GET | awk '{print substr($6,1,index($6,"<")-1)}'
Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244
GET | awk '{print substr($6,1,index($6,"<")-1)}'
Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244
- Status
Similar threads
