remove last column

[praywin]

Hi,
I want a awk script which will not print the last column of the line.
Say my input is

/usr/local/bin/gdb
/u/src/bin/ddd

I want the output to be

/usr/local/bin
/u/src/bin

awk -F/ '{for(i=1;i<NF;i++) {print &quot;/&quot;$i}}'

gives me

/usr
/local
/bin
/u
/src
/bin

I want them printed in one line at a time.
Any suggestions
Cheers,
Pravin.

 

[predamarcel]

awk -F/ '{for(i=1;i<NF;i++) {printf $i&quot;/&quot;}; printf &quot;\n&quot; }' < /tmp/in.txt __

http://marcell.hypermart.net/

___

 

[vgersh99]

nawk 'BEGIN{FS=OFS=&quot;/&quot;} {$NF=&quot;&quot;;print}' vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+