remove files smaller 36Kb

[Currando]

Hi,

I need a program that find the files in a directory smaller that 36KB and remove this files.

I make this line for this:

ls -l | awk '{print $5,$9}'|grep \^36 | awk '{print "rm",$2}' | sh

Anybody make this with less commands

Thanks

 

[Krunek]

Hi, Currando!

Please, try this command:

ls -l | awk '$5 > 36000 { print "rm", $9 }' | sh

Instead number 36000 you can put other number .

Bye!

KP. =-)

 

[grega]

You could use the unix find command to do this, e.g.

find . -type f -size -71 -exec rm {} \;

will find all files within (and under) your current directory with a size of 71 blocks or less (1 block=512 bytes, so 71 blocks is roughly 36Kb) and remove them.

Bear in mind that this commmand searches directories recursively from the start directory!!

If you just want to list the files it finds first to be sure, you can use the command

find . -type f -size -71 -exec ls -l {} \;

Greg.