regular expression

[lambros]

Hi,

How do I search $0 for the value of an array?

my script uses;

reg[1] = var

then later I have;

for (i in reg)
print reg

This works fine;

how can I search $0 for this value;

can I do;

if ($0 ~ /reg/) ?

 

[CaKiwi]

I assume this is awk. Your post is garbled because the

[i]

turned on italics. (uncheck the process TGML box or use j instead of i). But if I understand your post correctly, the answer is yes.

CaKiwi

 

[CaKiwi]

Upon further review, I now think the answer is no. Remove the slashes.

   if ($0 ~ reg[i]) ...

CaKiwi

 

[lambros]

Hi CaKiwi,

I've also tried this & it works to a point, however if I elaborate on it & do

if ($0 ~ reg && /78/)

it doesn't return anything, even thought this works on the command line ( when I insert the values returned by print reg... do you know why this is?

 

[jad]

if ($0 ~ reg[i] && $0 ~ /78/)