Regular Expression Problem

[pho01]

Suppose I have this line in a file name "temp.8639"
<!--Lab Accept Date-->Somedate

How do I run a sed command to replace this line with:

<!--Lab Accept Date-->Newdate

This is the command I used, but not worked:
cat temp.8639 | sed -e s/&quot;<!--Lab Accept Date-->\(.*\)&quot;/&quot;<!--Lab Accept Date-->Newdate&quot;/
Thanks!

 

[pavNell]

Here's an awk..

#!/bin/sh
NEWDATE=whatever_the_new_date_is
awk -v newdate=$NEWDATE -F> '{printf(&quot;%s%s\n&quot;, $1, newdate}' temp.8693


Here's a sed...

sed 's/\(!<--Lab Accept Date-->\).*/\1Newdate' temp.8693

 

[hallux]

Try this:
cat temp.8639 | sed 's/<!--Lab Accept Date-->\(.*\)/<!--Lab Accept Date-->Newdate/'
-Brent

 

[iribach]

not fish, nor cheese

note the &quot; instead of ' ans the '$'
#!/bin/sh
Newdate=`date` # or what ever you want
sed &quot;s/\(!<--Lab Accept Date-->\).*/\1$Newdate&quot; temp.8693

forget the cat|sed
sed is old enougth for opening inputfiles
sed ... filename