[Regex] Selecting content between round brackets, also including round brackets 1

[boqsc]

I'm gluing together a small block of bash code that would parse the output of gsettings get command.
I'm not sure what's wrong here.

This is the example of input. (gsettings get org.gnome.desktop.input-sources sources)

 [('xkb', 'us'), ('xkb', 'lt')]

This is the code that parses the input

#!/bin/bash
TEXT_TO_PARSE=$(gsettings get org.gnome.desktop.input-sources sources)
REGEX_PATTERN="\((.*?)\)"
while [[ ${TEXT_TO_PARSE} =~ (${REGEX_PATTERN}) ]]; do
	echo "${BASH_REMATCH[1]}"
	TEXT_TO_PARSE=${TEXT_TO_PARSE##*${BASH_REMATCH[1]}}
done

Expected output:

('xkb', 'us')
('xkb', 'lt')

The output I've got:

('xkb', 'us'), ('xkb', 'lt')

 

[feherke]

Hi

An additional binary operator, =~, is available, with the same precedence as == and !=. When it is used, the string to the right of the operator is considered a POSIX extended regular expression and matched accordingly (as in regex(3)).

Unfortunately non-greedy quantifiers are PCRE specific, not known by POSIX extended. So you will have to write it as :

[navy]REGEX_PATTERN[/navy][teal]=[/teal][i][green]"[/green][/i][lime]\([/lime][i][green]([^()]*)[/green][/i][lime]\)[/lime][i][green]"[/green][/i]

Feherke.
feherke.github.io

 

[boqsc]

Thanks, works as expected.