regex matching with regexp

[redbanditos1999]

Hi people !!

I need help for following problem:

how can I match "\%\w" in strings like

"hallo %hallo = 12U;"
"12 %12 = 0;"

but expect of strings like

printf("Today is the %d.%d.1998\n", pstruToday->sDay, pstruToday->sMonth);
printf("%d", xxx_ts_ExternCharArrayWrongType [2]);
printf ("%d >> 2 = %d\n", sSignedShift, sResult);

I need the "\%\w" to be relevant only outside of printf(...) sequences.


Many thanks for quick help !!!

redbanditos

 

[marsd]

proc NoPrintfMatches {fd} {
while {1} {
if {![eof $fd] && [gets $fd line] > -1} {
if {![regexp "printf\\(.*" $line]} {
if {[regexp "\%\\w" $line]} {
puts $line
}
}
} else {
break
}
}
close $fd
return
}

Good Luck

 

[redbanditos1999]

Thx for the answer Marsd !!

Im really sorry, but I didnt ever tell you what I really want to do ;-).
Im working on a syntax checker for C (Logiscope Tau Studio), where you can define your own rules for checking source files. The rules must be written in TCL mixed with special methods based on C-Language Data Model.
In my actual rule I need to match all binary operators, which dont have blanks after and before. So I have 2 regexp calls (after, before) which define regular expressions to find the operators. And now I only need the regular expression which allows me to find "%blahblah" or "%1234" in my source files text expect of using "%" in printf (like "%o" "%d" "%c" "%s" "%x&quot.
I've tryed diverse expressions but I couldnt take advantage.

redbanditos

 

[marsd]

Okay I'm a little confused..
You are still saying that printf() calls are
to be discriminated against only and that scanf(),
sprintf, etc..are okay?
All of these get picked up now:
scanf(" %f", &myplanet.gravity);
scanf(" %f", &myplanet.size);
scanf(" %f%f", &j, &m);

This will end that:
[regexp "\[a-zA-Z\]+\\(.*\%.*\\)]"

This will catch your % instances:
[regexp \%.*]

As for catching your % inside parens:
The best way is to write another negation pattern,
trying to exclude preceding parens like:
"\[^\\(.*\%\]" or "\[^\\(\]..*\%" fail.

You could try this to exclude modulo inside parens.
![regexp "\\(.*%\\)"