read output , search for text then print only the 3ed line after

[qqqqqq]

In AIX Korn shell with no nawk access, I would like to run the "tapeutil -f /dev/rmt0 inventory" command, search the output for a line containing the word "Slot" and print the line AND the 3ed line after the line that contains the work "Slot'. If this can be done as a one liner it would be great.
Example of data:
Source Element Address Valid ... No
Media Inverted ................. No
Volume Tag .....................

Slot Address 4116
Slot State ..................... Normal
ASC/ASCQ ....................... 0000
Media Present .................. No
Robot Access Allowed ........... Yes
Source Element Address Valid ... No
Media Inverted ................. No
Volume Tag .....................

Wanted output:
Slot Address 4116
Media Present .................. No

Thank You in Advance for your suggestions. I hope that I was clear and included all needed information.

 

[Salem]

Well if we can use those text strings to find the information, then this should work

tapeutil -f /dev/rmt0 inventory | egrep '^(Slot Address|  Media Present)'

 

[CaKiwi]

Or if you need the third line no matter what it is

awk '/^Slot/{print;for (i=0;i<3;i++) getline; print}'

CaKiwi

&quot;I love mankind, it's people I can't stand&quot; - Linus Van Pelt

 

[qqqqqq]

CAKIWI,
That is exactly what I wanted. So Perfect.........
I can even change it so that I can choose the next line or even the 5th line.