Read Input Into Array

[eb24]

It's been a super long time since I've gone down to a language like C (do .NET these days) and would really appreciate some assistance:

How can I input data at the command prompt and then parse out the strings with only using the <stdio.h> library and such string functions like strtok?

Input: This is just a test

Output:
This
is
just 
a
test

 

[GoAskAlice]

#include <stdio.h>
int main( int argc, char *argv[] ) {

	if( argc == 0 ) {
		puts( "No command line available." );
	} else {
	
		printf( "The program now running: %s\n", argv[0]);
		if ( argc == 1 ) {
			puts( "No arguements received on the command line." );
		} else {
	
			puts( "The command line arguements:" );
			int x;
			for( x = 1; x < argc; x++ ) {
				puts( argv[x] );
			}
	
		}

	}

}

This is taken from 'C in a Nutshell' - it uses only the stdio.h

Basically, to explain it there are two variables received in the function main();
argc is the number of arguements received on the command line.
argv[] stores these string command line input.

Basically, firstly argc will equal 1 if one command line option is entered - such as '<program_name> "This is test"'

But, remember, the first cell in the array is the name of the program, if the o/s does not send the name of the program, argv[0] is blank or <program_name>

There fore, command lines options start at argv[1] until argv[argv -1] (-1 because the last array cell in argv containts a null pointer)

Regards,

Alexander

 

[GoAskAlice]

Sorry, argc will equal TWO if a command line parameter was passed to the program.

 

[eb24]

GoAskAlice:

Wow! This is exactly what I am looking for! Thank you so much for your expeditious response!