Read a file line when it contains * 2

[Yarka]

Hi.
My script is such as:
$ ./a.sh input.txt
where a.sh has:

#!/bin/sh
out=/root/probe/out.txt
cat $1 |while read LINE
do
echo $LINE >> $out
done

and input.txt has:
111 666 888 000 999 * 66
3 3 999 * 8 8

each column is separated with tabulation.

The problem is when I execute my script. The output of out.txt is:

111 666 888 000 999 a.sh input.txt 66
3 3 999 a.sh input.txt out.txt 8 8

i.e., where there is * (in the input.txt file) puts the files of the current folder (/root/probe/).
How can I make so that it lists to me the line so as it has input.txt, reading the file line to line and without be able to change input.txt file?

Thanks.

 

[PHV]

and what about this ?
#!/bin/sh
out=/root/probe/out.txt
while read LINE
do
echo "$LINE"
done < $1 >> $out

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[Yarka]

Inside the while I need to have lines one to one. This is because of them I must extract values and to make a series of operations.


Thanks.

 

[PHV]

What do you want to do ?
I've replied your OP and don't see where I'm wrong ...

 

[feherke]

Hi

With or without the UUOC, the important for you are the double quotes ( " ) :

echo [red]"[/red]$LINE[red]"[/red]

But I suggest to listen to PHV regarding the redirecting too.

Feherke.

http://rootshell.be/~feherke/

 

[p5wizard]

Particularly, pay attention to the input/output redirection after the done keyword.

HTH,

p5wizard