re: parsing out data

[thutmose]

Hey,


Guys I am writing a script thats more like the du -k command.

ls -l | grep '^d' | awk '{print $9, $5, $3}'


my output is


size file name LOGON name

00 anyfile anyuser
123 awkscript anyuser
87 beber anyuser
7646 something anyuser


Is it a way to get the 3rd column to display the users real name rather than his logon ID.

 

[CaKiwi]

Replace your awk progam with:

BEGIN{
  FS=":"
  while ((getline < &quot;/etc/passwd&quot;) > 0) { usr[$1] = $5}
  FS=&quot; &quot;
}
{print $9, $5, usr[$3]}

Hope this helps. CaKiwi

 

[thutmose]

Hey,


thanks and I was wondering where I can get some well documented shell and awk scripts.

 

[CaKiwi]

There is an awk forum here with many awk solutions to problems, although they are not generally well documented. CaKiwi