Random Numbers

[sheronne]

I want to return a random numbers between lnLow and lnHigh (ex. 1 and 10) but I need to check for duplicate values, What is the quickest most efficient way?

In essence I want to return 1 through 10 in random order, not repeating a value.

 

[Cagliostro]

filling vector x with rand unical values:
include<vector>
using namespace std;
...........
//filling below:
vector<int> x;
vector<int>::iterator y;
for(int i=0;i<10;i++)
{
while(1)
{
int c=rand()%10+1;
y=find(x.begin(),x.end(),c);
if(y==x.end())
{
x.push_back(c);
break;
}
}
} John Fill

ivfmd@mail.md

 

[Zyrenthian]

I would create an array

int values[10]

for(int i=1;i<=10;i++)
{
values = i;
}

then use the random function to swap the values in the array n amount of times.

int temp,swap1,swap2;
for(int x = 0; x < times_to_swap; x++)
{
swap1 = rand%10;
swap2 = rand%10;

temp = values[swap1];
values[swap1] = values[swap2];
values[swap2] = temp;
}

On a side note you may want to seed the random fucntion with time

Matt

 

[Zyrenthian]

side note... my loop above is wrong... the internal of the loop with the values array intitialization should be

value[i-1]=i;

sorry... not enough coffee in me at the time of posting.



matt

 

[ggreg]

How about
srand (time(NULL))

numonetoten = 1 + rand()% (10 -1+1);

what you have above is
lowerbound + rand()% (upperbound - lowerbound +1)

i think you have to have #include <ctype.h>