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Random number output file
- Thread starter BrianCPP
- Start date
Code:
#include <stdio.h>
#include <stdlib.h>
void main()
{
FILE *fp;
fp = fopen("file.txt","w");
if(!fp)
{
fprintf( stderr, "Error while opening \"file\"");
exit(1);
}
for( i = 0; i < 50; i++ )
{
fprintf( fp, "%d\n", rand() % 50 );
}
fclose(fp);
}Well, here is a sample that generates a 5 by 6 array...aka lotto drawing....I'm not sure if this is what you are asking for......
#include <stdlib.h>
#include <stdio.h>
#include <time.h>
#include <iostream.h>
void GenerateNumbers( int lotto[][6] );
main()
{
int lotto[5][6], r, c;
srand(( unsigned ) time(NULL ));
GenerateNumbers( lotto );
for ( r=0; r < 5; r++ )
{
for ( c=0; c<6; c++ )
{
cout << lotto[r][c] << " ";
}
cout << "\n\n";
}
cout << "\n\n";
}
void GenerateNumbers(int lotto[][6] )
{
int num, r, c;
for ( r=0; r < 5; r++ )
{
for ( c=0; c<6; c++ )
{
num = rand() % 47;
lotto[r][c] = num;
}
}
}
#include <stdlib.h>
#include <stdio.h>
#include <time.h>
#include <iostream.h>
void GenerateNumbers( int lotto[][6] );
main()
{
int lotto[5][6], r, c;
srand(( unsigned ) time(NULL ));
GenerateNumbers( lotto );
for ( r=0; r < 5; r++ )
{
for ( c=0; c<6; c++ )
{
cout << lotto[r][c] << " ";
}
cout << "\n\n";
}
cout << "\n\n";
}
void GenerateNumbers(int lotto[][6] )
{
int num, r, c;
for ( r=0; r < 5; r++ )
{
for ( c=0; c<6; c++ )
{
num = rand() % 47;
lotto[r][c] = num;
}
}
}
- Status
