Question using fgetc();

[Netherbeast]

I'm trying to get the Decimal value of an Ascii char being read by fgetc() like this...

int theChar = 0;//the character being read
FILE *fp = fopen("poly.txt", "r"//file being read

while(theChar=fgetc(fp) != EOF) {
printf("theChar=%d\n", theChar);
}

but when it prints, it only prints the value 1.
I'm just a begining programmer and don't understand everything yet. Pointers are hard for me too.

Netherbeast

 

[olded]

Netherbeast:

This works under Solaris 7 Unix:

#include <stdio.h>

int main()
{
int theChar;
FILE *fp;

if((fp = fopen(&quot;poly.txt&quot;, &quot;r&quot) == NULL)
{
printf(&quot;can't open file\n&quot;
exit(1);
}

while((theChar=fgetc(fp)) != EOF) {
printf(&quot;theChar=%c\n&quot;, theChar);
}

fclose(fp);
}

You have major problems:

1) You need an extra set of () around:
((theChar=fgetc(fp))

2) From the man page:
The fgetc() function obtains the next byte (if present) as
an unsigned char converted to an int, from the input stream
pointed to by stream,

This means since theChar is an int, you have to use the character &quot;c&quot; agrument of printf.

Regards,


Ed

 

[Netherbeast]

Thanks, that worked.