Question on Subnetting(didn't know where to post this) 2

[BlackEvoVii]

If this is in the wrong forum, i apologize, i didn't knwo where this should go.

This is an assignment for one of my classes.

I have a Class C Address of 221.0.101.0

with the following information

FDDI Backbone with 7 servers, 3 LANS in a 3 story building along with a 256 kbps point-to-point Fractional T1 line. Assume the point-to-point is part of the class c address space.

Lan 1 consists of 24 Workstations and 4 printers along with a 7 port switch

Lan 2 consists of 51 workstations and 8 printers and is on a bridged LAN. Each of the 51w and 8p must be distributed as evenly as possible upon 4 segments.

and Lan 3 has 11 workstations with 2 printers

My Questions.

There is more than one physical segment right? If this is true, than the class c address given to me, can not be used properly to accomodate all these LANs?

A switch would be considered a node?

and would the bridges, severs and FDDI get their own ip addresses?

 

[wybnormal]

A switch can be node once it has a IP address for management. Yes, you have multiple physical segments. Yes, most network equipment would get their own IP address.. tho' most hubs are stupid and not managable so no IP is needed for them.

I suggest you read up on subneting and VLSM (variable length subnet mask). You will take the one class C address and break it into a number of segments(subnets). You then take one of the subnets and apply yet another mask to it and break it into more subnets. So it's like a tree with branches.

http://www.packetattack.com/tutorials.html

near the bottom is a link to a nice tutorial.
192.168.50.0 255.255.255.0 class C address 254 hosts

If you need to subnet the class C, then you would do something like this:

192.168.50.0 255.255.255.224 you get 8 subnets from this one IP address.
Subnet Mask Subnet Size Host Range Broadcast
192.168.50.0 255.255.255.224 30 192.168.50.1 to 192.168.50.30 192.168.50.31
192.168.50.32 255.255.255.224 30 192.168.50.33 to 192.168.50.62 192.168.50.63
192.168.50.64 255.255.255.224 30 192.168.50.65 to 192.168.50.94 192.168.50.95
192.168.50.96 255.255.255.224 30 192.168.50.97 to 192.168.50.126 192.168.50.127
192.168.50.128 255.255.255.224 30 192.168.50.129 to 192.168.50.158 192.168.50.159
192.168.50.160 255.255.255.224 30 192.168.50.161 to 192.168.50.190 192.168.50.191
192.168.50.192 255.255.255.224 30 192.168.50.193 to 192.168.50.222 192.168.50.223
192.168.50.224 255.255.255.224 30 192.168.50.225 to 192.168.50.254 192.168.50.255

You can take 1 of these subnets and subnet it again if needed.

MikeS Find me at

http://www.packetattack.com

"Take advantage of the enemy's unreadiness, make your way by unexpected routes, and attack unguarded spots."
Sun Tzu