question about awk 1

[linuxMaestro]

I am trying to awk the first number.

line="51 requests currently being processed, 9 idle servers";
num=awk($line,\d*);
if ($num>200)
mail linux@maestro.com

what is the correct syntax for awk to grep the 51 from the line above?

 

[vgersh99]

#!/bin/ksh

line="51 requests currently being processed, 9 idle servers";
num=awk($line,\d*);
if [ $(echo "${line}" | awk '{print $1}) -gt 200 ]; then
mail linux@maestro.com
fi;

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[linuxMaestro]

Thank you for this valuable post!

 

[PHV]

No awk needed at all:
line="51 requests currently being processed, 9 idle servers"
set -- $line
if [ $1 -gt 200 ]; then
mail linux@maestro.com
fi

Hope This Help, PH.
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