program

[swaroop]

Here is a statement
cout << &quot;Variable Name : &quot; << Variable << endl;
I wanted to change that to
PN(Variable);
I wanted the same result.

Could any one give Idea(program ) for this.

Thanks in advance.

Swaroop.

 

[801119]

YOu could always try to define it, something like this:

#define PN(variable) cout << &quot;Varialbe name : &quot; << variable << endl;

all you need to do from here is to call
PN(/*statement here*/)

PN(&quot;HELLO&quot // this would give the result

Varialbe name : HELLO Martin G Broman
mgb_svea@thevortex.com

DWS - Alpha Whitin Dead Wolf Society
Xaner Software, DB programer

 

[Sorry]

Thankyou for your reply.

There was a typographical error in my program.

I want to see the program as shown example below.

#include <string.h>
.
.
.

char *Variable;

strcpy(Variable, &quot;Swaroop&quot;
PN(Variable);
.
.
.

For the above statement I want the RESULT as

Variable : Swaroop

That I was expecting.

Regret my mistake.

 

[rajji]

if u don't want to use cout to print u can always overload insertion operator and use any thing u want

 

[2ffat]

Do you mean something like:

void PN (string Something)
{
    cout << &quot;Variable Name : &quot; << Something << endl;
}

.
.
.

int main()
{
    string Variable = &quot;Swaroop&quot;;
    PN(Variable);
    return 0;
}

James P. Cottingham

http://www.ivcusa.com

 

[Guest_imported]

Thank you for reply.

But The output of your code will give a result look something like this

Variable Name : Swaroop

I wanted my code output have to give a result look something like this

Something : Swaroop

I think you got my point.

 

[801119]

So the varialbe thing is just the name for a variable??
such as integers, char string etc.?? Martin G Broman
mgb_svea@thevortex.com

DWS - Alpha Whitin Dead Wolf Society
Xaner Software, DB programer